So I was pondering this morning? Can there be another interger other than one already existing that multiplies by another interger to give the same product. In other wrods, can the equation exist.
The anser is no. And here's why: if you divde all intergers by b, you get
Feel free to tell me how stupid I am in the comments below! :) --Slow Reader (talk) 16:52, April 14, 2015 (UTC)