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9+10=09+10=((0+1)*10)+((9+0)*1)=(1*10)+(9*1)=19
Maart1781 is absolutely right, if you use length^n terms conversion changes from u to u^n.
First we need to think of time raised to powers.t^n means multiplying n time intervals together. We know that distance/time equals velocity, distance/time^2 equals acceleration,etc distance/(time^n) equals the nth derivative of length with respect to time. s^n is a unit of time^n. time^n can be thought of as variance in time^(n-1).
9^log_5(x-1) - 5^log_9(x+3)=4->((9^1/log(5))^log(x-1))-(((5^1/log(9))^log(x+3))=4, if we change to base e then hen simplifying we get (x-1)^(ln(9)/ln(5))-(x+3)^(ln(5)/ln(9))=4, to solve for x, x-1 must be 5 and x+3 must 9,therefore x=6.
Find a in 3a+4=16 can be thought of as the point as which 3x+4 and 0x+16 intersect at .This is the same as where 3x and 12 intersect which is the same as where x and 4 intersect at which means a=4
Not even close to pi, I can approximate pi~3.14159265358979323946264338327950288419796
1 according to the Riemann Sphere.
23
Please don't tell me I need to code a pentation calculator now it's getting near g(1) at this point.
I did make a calculator that can handle a^^b for integer b(including -2,-3 by adding new number systems that have bigger cardinality than the reals) but I never hosted it. Also it's O(bd) where b and d are non-constant
Well you could since there are alternate number systems, such as p-adics,etc.
I choose 5 since 0123456789X->01392784X5 is created with a real series.
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