All posts by BobGames08

Don't you mean a^2 + b^2 ?

Ok, i'm gonna hold 0

10000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000

None of these, x needs to be 51 which doesn't appear

The cube root of x is x, but x^2 is not 1

What 2 values of x statisfy both these rules?

1: yes, duh

2: yes, ends in 0

4: yes, ends in 00

5: yes, ends in 0

8: yes, ends in 000

25: yes, ends in 00